Skool Mathematics I - August 14th, 2008
= x + x^2 + x^3 + … + x^n
= x (1 + x + x^2 + … + x^(n-1))
= x ((x^n – 1)/(x – 1))
Posted under Engineering
= x + x^2 + x^3 + … + x^n
= x (1 + x + x^2 + … + x^(n-1))
= x ((x^n – 1)/(x – 1))
Posted under Engineering
I'm Gurinder nesting in UK working as a Software Engineer in Telecom. I started this blog to note down my activities; mainly regarding financial engineering and news. It's not to advise someone, just mear to record for myself; although comments are more than welcome. More interested in my life its here.